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Q:

F#: why is count 0 in a foreach loop if there is more than one element in an array of custom types?

I’ve got an array of an array of custom types.
The fields of the custom types are the type of the next element in the array:
//foreach (array item in array) {
let arr = [| [| “a”; “b”; “c”; “d” |]|]
let count = arr |> Array.count
printfn “%d” (count);
//}

This prints 0 for me, despite the fact that the count of the two outermost arrays is 2 and there are 4 elements in the inner array.
I found it kind of confusing that count is 0, although the way I wrote the code suggests that I should get 2.

A:

If you look closely at the definition of count on Array.fs, you can see that the first parameter is the type of the whole array, and the second is a predicate (one of the type Typer*) which is applied to each element to check for membership in the array.
The interesting thing in your case is that – for each element – count passes over the elements of the array twice (once for each parameter) in order to compute whether it is in the array.
In other words, when you write
Array.count [| [| “a”; “b”; “c”; “d” |]|]

You are asking for the count of the elements of the array – in particular, the count of “c” – which is just 0.

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